Having two cases in a switch statement or two branches in an if chain with the same implementation is at
best duplicate code, and at worst a coding error. If the same logic is truly needed for both instances, then in an if chain they should
be combined, or for a switch, one should fall through to the other.
switch ($i) {
case 1:
doSomething();
break;
case 2:
doSomethingDifferent();
break;
case 3: // Noncompliant; duplicates case 1's implementation
doSomething();
break;
default:
doTheRest();
}
if ($a >= 0 && $a < 10) {
doTheThing();
else if ($a >= 10 && $a < 20) {
doTheOtherThing();
}
else if ($a >= 20 && $a < 50) {
doTheThing(); // Noncompliant; duplicates first condition
}
else {
doTheRest();
}
if ($b == 0) {
doOneMoreThing();
}
else {
doOneMoreThing(); // Noncompliant; duplicates then-branch
}
var b = a ? 12 > 4 : 4; // Noncompliant; always results in the same value
switch ($i) {
case 1:
case 3:
doSomething();
break;
case 2:
doSomethingDifferent();
break;
default:
doTheRest();
}
if (($a >= 0 && $a < 10) || ($a >= 20 && $a < 50)) {
doTheThing();
else if ($a >= 10 && $a < 20) {
doTheOtherThing();
}
else {
doTheRest();
}
doOneMoreThing();
b = 4;
or
switch ($i) {
case 1:
doSomething();
break;
case 2:
doSomethingDifferent();
break;
case 3:
doThirdThing();
break;
default:
doTheRest();
}
if ($a >= 0 && $a < 10) {
doTheThing();
else if ($a >= 10 && $a < 20) {
doTheOtherThing();
}
else if ($a >= 20 && $a < 50) {
doTheThirdThing();
}
else {
doTheRest();
}
if ($b == 0) {
doOneMoreThing();
}
else {
doTheRest();
}
int b = a ? 12 > 4 : 8;
Blocks in an if chain that contain a single line of code are ignored, as are blocks in a switch statement that contain a
single line of code with or without a following break.